which of the following fractios is the greatest
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This problem can be solved in 2 ways.
1st :-
a=3–√+2–√3–√−2–√
=(3–√+2–√)(3–√+2–√)(3–√−2–√)(3–√+2–√)
=(3–√+2–√)23−2
=((3–√)2+(2–√)2+2(3–√)(2–√)
=3+2+26–√
=5+26–√
b=3–√−2–√3–√+2–√
=(3–√−2–√)(3–√−2–√)(3–√+2–√)(3–√−2–√)
=(3–√−2–√)23−2
=((3–√)2+(2–√)2+−2(3–√)(2–√)
=3+2−26–√
=5−26–√
Now
a2+b2
We know that
(x+y)2=x2+y2+2xy
⟹x2+y2=(x+y)2−2xy
If we take x=a and y=b then
a2+b2
=(a+b)2−2ab
=(5+26–√+5−26–√)2−2((5+26–√)(5−26–√))
=(10)2−2(25−24)
Here we use identity
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