Question

Which of the following gas has vapour density twice of CH4:-
A SO2
B 02
C N2
D CO2​

Answer 1

Answer:

I think it shoud be O2

Explanation:

vapour density =moucular weight /2

CH4=16/2=8

O2=32/2=16

Answer 2

Answer:

Option (B) O₂ is correct.

Calculations:

We know the formula of vapor density is $\frac{Molecular Mass}{2}$.

The vapor density of CH₄ is → $\frac{12+1+1+1+1}{2}$ = 8

Twice of 8 is 16

Option A: SO₂ has the vapor density $\frac{32+32}{2}$ = 32

Option B: O₂ has the vapor density $\frac{32}{2}$ = 16

Option C: N₂ has the vapor density $\frac{28}{2}$ = 14

Option D: CO₂ has the vapor density $\frac{12+32}{2}$ = 22

Result:

We see that the vapor density of O₂ is exactly twice of vapor density of CH₄; hence, Option (B) O₂ is correct.