Question

which of the following has highest bond-dissociation energy?
a)F-F
b)Cl-Cl
c)Br-Br
d)I-I

Answer 1

The answer is a Because fluorine being smallest among halogens has highest electronegativity and thus binds strongly to another fluorine atom.Hence F-F bond requires higher amount of energy to break the bond.

# Hope it helps.

# Follow me.

Answer 2

Answer: Option (a) is the correct answer.

Explanation:

The amount of energy necessary to break a chemical bond  through homolytical fracture is known as bond dissociation energy.

Smallest is the size of combining atoms more tightly the electrons will be held by them. Hence, there will be a strong bond between the combining atoms.

As a result, more heat will be required to dissociate the bond.

On the other hand, larger is the size of combining atoms more weak bonding will be there because electrons of both the combining atoms are not held tightly.

Due to this, the bond will break with less amount of heat energy.

thus, we can conclude that out of the given options, F-F has highest bond-dissociation energy.