Question

Which of the following has smallest number of molecules a) 11.2 L of O2 at NTP b) 8.0 g of O2 c) 0.1 mole of O2 d) 2.24×10^24 ml of O2

Answer 1

hey friend here is your answer^^

(a) 11.2 L at NTP means 0.5 moles { 11.2/22.4}
(b)8g of O2 means 0.25 moles {8÷ 32}
(c) 0.1 moles
(d) 2240ml of O2 gas means= 1 mole

as no. of molecules is = no. of moles × Avogadro no.

hence clearly (d ) option is correct

hope u understood
have a nice day
plz mark brainiest★★

Answer 2

Answer:

The correct answer is Option C : $0.1$ mole of $O_{2}$

Explanation:

One mole of a substance $= 6.022 * 10^{23}$ units of that substance.

• Option A : $11.2$L of $O_{2}$ :

    We know that $1$ mole of a gas at NTP occupies $22.4$L as volume.

    Hence $11.2$L of $O_{2}$ will have $0.5$ mole of $O_{2}$.

• Option B : $8.0$g of $O_{2}$ :

   We know that the mass of $O_{2}$ is $16g+16g = 32g$

   $32$g of $O_{2}$ will contain $1$ mole of $O_{2}$

   $8$g of $O_{2}$ will contain $8/32=0.25$ mole of $O_{2}$.

• Option C – Given that it is $0.1$ mole of $O_{2}$.

• Option D - $2.24*10^{24}$ ml of $O_{2}$

   We know that 1 mole of a gas at NTP occupies $22.4$L as volume.

   $2.24*10^{24}$ ml of $O_{2}$ contains  $2.24*10^{24} /22400 = 1.E20$ mole

Hence we can find out that Option C - $0.1$ mole is the smallest among these.