Question

which of the following has the largest number of particles a) 4.4 g of co2 b) 8 g of ch4 c) 2 g of h2 d) 34.2 g of c12h22o11 if you answer this question i will mark you the branliest so please help me

Answer 1

Answer:

CORRECT ANSWER IS OPTION (D)

Step-by-step explanation:

Wt Of one mole ofCH4= (12+4)=16gm *-//- of CO2 = ( 12 + 32 )= 44gm *- // - of C12H22O11 = ( 12* 12 + 22+ 16 *11) = 144 + 22 + 176 = 342 gm* - // - of H = 1 gm. **** 2 moles of H for 2 gm # in all given options Except D,,,,, given molecules are less than there 1 mole in concentration. while H has two moles ,,,,means 2* Na ( N =Avagadro no. ) that means 2* 6.022 * 10^23 atoms or particles of H. which are more or largest as compared to other options.

Answer 2

Answer:

iska ans hoga 34.2g of c12h22o11