which of the following has two equal roots
x square - 2 x minus 1
x square - 2 X + 1
2 x square - 2 X + 1
x square - 2 x minus 3 is equal to zero
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Answer:
x²-2x+1
Explanation:
Compare x²-2x+1 with ax²+bx+c we get,
a = 1 , b = -2 , c = 1
Discreminant (D) = b²-4ac
=(- 2)²-4×1×1
= 4 - 4
= 0
D = 0
Therefore,
x²-2x+1=0 has real and equal roots
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