Question

which of the following is dimensionally correct. 1)y=sin(2πt/T)
2)Y=a sin (vt)
3)Y=a/T sin (a/t)
4)Y=a(sin2πt/T+cos2πt/T)​

Answer 1

Answer:

(d) y = (a√2) (sin 2πt / T + cos 2πt / T ) ... Dimension of y = M0 L1 T0 ... Hence, the given formula is dimensionally correct. ... y = a sin vt

Answer 2

Answer:

Chack the attachment for uour answer.