which of the following is dimensionally correct. 1)y=sin(2πt/T)
2)Y=a sin (vt)
3)Y=a/T sin (a/t)
4)Y=a(sin2πt/T+cos2πt/T)
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(d) y = (a√2) (sin 2πt / T + cos 2πt / T ) ... Dimension of y = M0 L1 T0 ... Hence, the given formula is dimensionally correct. ... y = a sin vt
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