Which of the following is dimensionally correct?
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Answered by
0
Answer:(2)
Explanation:
Dimensions of mv^2/r is [ M][L^2T^-2]/[L^2]
=[MLT^-2]
Answered by
0
Answer:
(2) is the correct answer.
Explanation:
We know that F=ma
Hence it's dimensions are [M][LT^-2].
In the following options, only (2) gives the same answer.That is,
F=(mv^2)/r
F=[ML^2 T^-2]/[L].
=>F=[M][LT^-2].
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