Question

Which of the following is irrational
a. 3 ⎻ 4 /√5
b. √8 ⎻ 3
c. 4 + 4 /√9
d. √4 ⎻ √2​

Answer 1

Answer:

option a is irrational

Step-by-step explanation:

I hope it helps

Answer 2

Given:

$a)3-4/\sqrt{5} \\b)\sqrt{8} -3\\c)4+4/\sqrt{9}\\d)\sqrt{4} -\sqrt{2}$

We have to find the irrational number from the above equations.

• As we know that the irrational numbers are all real numbers that are not rational numbers.
• Irrational numbers cannot be expressed as the ratio of two integers.

We are solving in the following way:

We have,

$a)3-4/\sqrt{5} \\b)\sqrt{8} -3\\c)4+4/\sqrt{9}\\d)\sqrt{4} -\sqrt{2}$

Now,

$a)3-4/\sqrt{5}\\\\\Rightarrow 3-\frac{4}{\sqrt{5} }$

$b)\sqrt{8} -3\\\Rightarrow 2\sqrt{2} -3\\\\\Rightarrow2.82-3\\\Rightarrow -0.071$

$c)4+4/\sqrt{9}\\\\\\\Rightarrow 4+\frac{4}{\sqrt{9} } \\\\\Rightarrow4+\frac{4}{3} \\\\\Rightarrow\frac{16}{3}$

$d)\sqrt{4} -\sqrt{2}\\\\\Rightarrow 2-\sqrt{2} \\\Rightarrow 2-\sqrt{2}$

Solving the above equation further we get,

The irrational number from the above equations is$b)\sqrt{8} -3 \ and\ d)\sqrt{4} -\sqrt{2}$

Hence, the irrational numbers are$b)\sqrt{8} -3 \ and\ d)\sqrt{4} -\sqrt{2}$.