which of the following is not a vector space
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Answer:
Let S={→a}, where →a≠→0. Hence, →a+→a∉S. Thus, S is not a vector space.
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Answer:
hii
Step-by-step explanation:
the the set of pointer (x y z) Er3 satisfying a x + y + z equal to one is not a vector space because it isn't in it
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