Question

which of the following is the strongest base : La(OH)3 ; Pr(OH)3 ; Ce(OH)3; Lu(OH)3​

Answer 1

Answer:

The strongest base is found to be the option (i) $La (OH)_3$

Explanation:

We know that because of the lanthanoid contraction, the dimensions of the tri-positive lanthanoid ion ($M^{3+}$) often decreases with boom/increase in atomic number variety, i.e., from $La^{3+}$ to $Lu^{3+}$. It consequences in decrease of basic nature from $La^{3+}$ to $Lu^{3+}$. The individual ionic nature of the M-OH bond decreases and the individual covalent character will progressively increase.

As a conclusion, the primary basic strength of the lanthanoid hydroxides decreases from ​$La (OH)_3$ to $Lu (OH)_3$.

Thus $La (OH)_3$ is the strongest base.

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Answer 2

Answer:

$La(OH)_3$ is the strongest base.

Explanation:

• Due to the contraction of the lanthanoid, the size of the tri-positive lanthanoid ion ($M^{3}$) regularly decreases with an increase in atomic number.

• It causes the basic character to drop from $La^{3+}$ to $Lu^{3+}$.

• The ionic character of the M-OH bond decreases and the covalent character of the M-OH bond gradually increases.

Therefore, the basic strength of the corresponding hydroxides decreases from $La(OH)_3$  to $Lu(OH)_3$  . Therefore, $La(OH)_3$ is the strongest base.

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