which of the following is the value of k if the roots of xsqare + kx+k=0are real and equal
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Answer:
k = 4
Step-by-step explanation:
In the quadratic equation ax² + bx + c = 0
If b² - 4ac = 0, the roots are real and equal
The given equation is:
x² + kx + k = 0
Comparing it with standard form,
a = 1, b = k, c = k
b² - 4ac = 0
=> k² - 4(1)(k) = 0
=> k² - 4k = 0
=> k(k - 4) - 0
k = 4 or k = 0
k cannot be equal to zero, hence k = 4
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