Question

Which of the following is true if the arithmetic Mean, Median and Mode of a frequency
distribution are x, y and z respectively.
a) x-z =3(x-y). b) z-x = 3(x-y)
c)z-x =3(y-x). d)x-z =3(y-z)​

Answer 1

Step-by-step explanation:

Mode = 3 Median - 2 Mean

Z=3M−2X

Given,

M

X

=

8

9

X=

8

9M

Therefore,

Z=3M−2×

8

9M

=3M−

4

9M

Z=

4

3M

Therefore,

Z

M

=

3

4

M:Z=4:3