Chemistry, asked by sristhi23, 1 year ago

which of the following metals do not evolve H2 from dil. acid 1)A(E°A+/A=0.25V)
2)B(E°B/B+=+0.22V)
3)C(E°c+/c=-0.30V)
4) D(E°D/D+=+0.44)..here E°=electrode potential

Answers

Answered by ranjanalok961
14
Answer of this quedtion is 1
Attachments:

sristhi23: no the correct answer is 1st option
sristhi23: i could not understand how
sristhi23: ☺️thnks for effort buddy
sristhi23: bruh..i was thanking you for you effort..anyways
Answered by enigma37
8

Answer:

option 1

Explanation:

Comparing the reduction potential with standard Hydrogen Electrode,

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.[The metals which have negative SRPs , can only liberate H2 ]

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.[The metals which have negative SRPs , can only liberate H2 ]now, considering the options given (Aakash Study package) , the answer will be option 1

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.[The metals which have negative SRPs , can only liberate H2 ]now, considering the options given (Aakash Study package) , the answer will be option 1(as option 3, option 4, option 2 have negative SRPs)

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.[The metals which have negative SRPs , can only liberate H2 ]now, considering the options given (Aakash Study package) , the answer will be option 1(as option 3, option 4, option 2 have negative SRPs)( SRP= -SOP)

Comparing the reduction potential with standard Hydrogen Electrode,The one having higher reduction potential (SRP)will not allow H+ to be reduced. Thus, there'll be no production of H2.[The metals which have negative SRPs , can only liberate H2 ]now, considering the options given (Aakash Study package) , the answer will be option 1(as option 3, option 4, option 2 have negative SRPs)( SRP= -SOP)HOPE IT WORKS! MARK IT BRAINLIEST PLS!

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