Which of the following number is the additive inverse of 7/129
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Answer:
-7/129
Step-by-step explanation:
We know that the additive inverse of a number is the number by which if we add the original number the sum is equal to 0.
For example the additive inverse of "a" is "-a"
because when we add "a" and "-a" the sum is equal to 0: a+(-a)
a-a= 0
So thus the additive inverse of any positive number is the negative of that same quantity and vise versa. So the additive inverse of 7/129 is the number by which if we add it the solution is 0.
So it will be -7/129 be 7/129+(-7/129)=0
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