Math, asked by myselfhimanshuk760, 9 months ago

Which of the following numbers are perfect cubes?
(i) 4096 (ii) 108 (iii) 392
(iv) – 27000 (v) 64
1331

Answers

Answered by abhaynigam2013
10

Answer:

4096 ,-27000, 64, 1331

Answered by PADMINI
29

Given:

i) 4096 (ii) 108 (iii) 392

(iv) 27000 (v) 64

1331

To Find :

Which of the given numbers are perfect cubes?

Solution :

1) 4096 (iv) 27000 (v) 64 (vi) 1331 are perfect cubes.

cube means we should multiply the number itself three times.

 =  >  {16}^{3}  = 16 \times 16 \times 16 = 4096

 =  >  {30}^{3}  = 30 \times 30 \times 30 = 27000

 =  >  {4}^{3}  = 4 \times 4 \times 4 = 64

 =  >  {11}^{3}  = 11 \times 11 \times 11 = 1331

Hence, 4096, 27000, 64 and 1331 are perfect cubes.

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