Which of the following orbitals does not exit? 6s,3p,2d,4f
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Answered by
5
Answer:
2d
Explanation:
since for an n value,upto n-1 orbitals are possible
that for n=2 the value of l are upto 2-1=1.....0 ,1 are possible that is s and p are possible
Answered by
1
2d orbital does not exists as 2 which is principal quantum number also denoted by (n)
can contain maximum 8 electron by using the formula 2n^2 i.e. (2*2^2)=8 . 2s orbital contains 2 electron and 2p orbital contains 6 electron which gives the sum 8. Thus, 2d orbital does not exist.
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