Question

Which of the following overlapping is not present in Xeo3 molecule a)sp3 Px b)sp3 Py c)dxz px d)sp3 s

Answer 1

Therefore the hybridisation is Sp^3

Explanation:

As we know that

Z = (Number of valence electrons on central atom) + (number of monovalent groups attached) - (charge with sign)

Now, divide Z by 2.

If Z/2 = 2 sp

Z/2 = 3 sp^2

Z/2 = 4 sp3

Z/2 = 5 sp^3d

Z/2 = 6 sp^3d^2

Now lets use this to figure out the hybridization of XeO3

• Central atom: Xe
• Number of Valence electrons = 8
• Mono-valent groups attached = 0 (Because Oxygen is bivalent)
• Charge = 0

Z = 8

Z/2 = 4

Therefore the hybridisation is Sp^3

Answer 2

Answer:dxz+ px

Explanation:

See, in hybridisation, 4 orbitals of the outermost shell of Xe have been used-

5s, 5px, 5py, 5pz....(Note- Hybridisation is seen only in outermost shell.So, 4d of Xe won't be included)

Now, we have 4 hybrid orbitals. 3 are used in formation of sigma bonds with 3 oxygen atoms and, the 4th exists as a lone pair..

Now, oxygen is joined with a double bond. One is sigma and, other is π. As hybrid orbitals always form sigma bonds(except In benzyne), So, the π bond is formed between atomic orbitals of Xe and O.

O's outermost orbitals are 2p and Xe's are 4d . so, π bonding is there between 2p and 4d......

And, sp3-s bond can't be there bcoz hybrid orbs have overlapped with p- orbitals.

HOPE IT HELPS..