Question

Which of the following oxides is most acidic?




A )
Cl2O


B )
Cl2O5


C )
Cl2O7


D )
Cl2O3



Let the oxidation state of Cl in the given oxides bex.

Cl2O

2x 2 = 0

x= 1

Cl2O5

2x 10 = 0

x= 5

Cl2O7

2x 14 = 0

x= 7

Cl2O3

2x 6 = 0

x= 3

Greater the oxidation state, greater is the acidic strength.



in this question why have we taken 2x nd subtracted itfrom two thn 14 and so on??? :O

Answer 1

Cl2O7
take chlorine oxidation state x

oxygen oxidation state _2

2x+7×_2 =0

2x=14
x=+7

Answer 2

Hey dear,

● Answer -
c) Cl2O7

● Explaination -
Let's calculate oxidation state of Cl atom in all oxides.
We'll take OS of O as -2 and that of Cl as x.

In Cl2O,
2×x + 1(-2) = 0
2x - 2 = 0
x = +1

In Cl2O5,
2×x + 5(-2) = 0
2x - 10 = 0
x = +5

In Cl2O7,
2×x + 7(-2) = 0
2x - 14 = 0
x = +7

In Cl2O3,
2×x + 3(-2) = 0
2x - 6 = 0
x = +3

Higher the oxidation state higher acidic strength, therefore Cl2O7 is more acidic than others.

* As to your doubt, sum oxidation state of all ions in compound is equal to charge on it. That's why here total sum is taken 0 .

Hope this helps you...