Question

Which of the following pair is expected to have the same bond order and why? (i) O2 , N2 (ii) O2 + , N2 – (iii) O2 – , N2

Answer 1

there ans is(i)O2 ,N2 plzz mark me brainliest ans

Answer 2

Answer:

The correct answer is (ii)$O^{2+} ,N^{2-}$

It can be calculated by the formula: $\frac{(N_{b}-N_{a})}{2}$

where , $N_{a}$= number of electrons in bonding orbitals

$N_{b}$= number of electrons in anti-bonding orbital

For $O^{2+}$,

$N_{a}$ = 10

$N_{b}$ =5

Bond order= (10-5)/2=2.5

For $N^{2-}$,

$N_{a}$=5

$N_{b}$=10

Bond order=(10-5) = 2.5

Hence, (iii) $O^{2+} ,N^{2-}$ is the correct answer.

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