Which of the following polynomials has -3 as a zero?
A.
x^2 + 3
B.
(x – 3)
C.
x^2 – 9
D.
x^2 – 3x
Answers
Answered by
6
Hi Rehan......
If any of these polynomial has - 3 as it's zero , then when we substitute - 3 in the place of x , we will get zero....
in option A
x² + 3
= ( - 3 )² + 3 = 9 + 3 = 6 ≠ 0 .... so option A is not
------------------------------------
In option B
x - 3 = - 3 - 3 = - 6 ≠ 0 .... so option B is not
-------------------------------------
In option C
x² - 9 = (-3)² - 9 = 9 - 9 = 0 ...so option C is a polynomial which has - 3 as a zero..
------------------------------------------
In option D
x² - 3x = 9 + 9 = 18 ≠ 0..... so option D is not
---------------------------------
So your answer is Option C....
hope it helps
If any of these polynomial has - 3 as it's zero , then when we substitute - 3 in the place of x , we will get zero....
in option A
x² + 3
= ( - 3 )² + 3 = 9 + 3 = 6 ≠ 0 .... so option A is not
------------------------------------
In option B
x - 3 = - 3 - 3 = - 6 ≠ 0 .... so option B is not
-------------------------------------
In option C
x² - 9 = (-3)² - 9 = 9 - 9 = 0 ...so option C is a polynomial which has - 3 as a zero..
------------------------------------------
In option D
x² - 3x = 9 + 9 = 18 ≠ 0..... so option D is not
---------------------------------
So your answer is Option C....
hope it helps
anshika1020:
hehe..
Answered by
4
hello...
Question :- Which of the following polynomials has -3 as a zero?
A.
x^2 + 3
B.
(x – 3)
C.
x^2 – 9(✔️)
D.
x^2 – 3x
EXPLANATION
(A) P(x) = x² + 3
p(-3) = (-3)² + 3
p(-3) = 9 + 3
= 12 ≠ 0
Hence option A is not the correct option.
(B) p(x) = (x – 3)
p(-3) = ( - 3 - 3 )
p(-3) = -6
-6 ≠ 0
Hence option B is not the correct option.
(C) p(x) = x^2 – 9
p(-3) = (-3)² - 9
p(-3) = 9-9
0 = 0
Hence option C is correct option
(D) p(x) = x^2 – 3x
p(-3) = (-3)² - 3(-3)
p(-3) = 9 - 6
3 ≠ 0
Hence option D is not correct option
Question :- Which of the following polynomials has -3 as a zero?
A.
x^2 + 3
B.
(x – 3)
C.
x^2 – 9(✔️)
D.
x^2 – 3x
EXPLANATION
(A) P(x) = x² + 3
p(-3) = (-3)² + 3
p(-3) = 9 + 3
= 12 ≠ 0
Hence option A is not the correct option.
(B) p(x) = (x – 3)
p(-3) = ( - 3 - 3 )
p(-3) = -6
-6 ≠ 0
Hence option B is not the correct option.
(C) p(x) = x^2 – 9
p(-3) = (-3)² - 9
p(-3) = 9-9
0 = 0
Hence option C is correct option
(D) p(x) = x^2 – 3x
p(-3) = (-3)² - 3(-3)
p(-3) = 9 - 6
3 ≠ 0
Hence option D is not correct option
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