Question

which of the following Qudratic polynomial has -3 and 4 as its Zeroes

a) x^2-x+12
b) x^2+x+12
c) x^2/2-x/2-6
d) 2x^2+2x-24

Answer 1

$let \: zeroes \: be \: \alpha \: and \: \beta \\ \alpha = - 3 \: \: \: \: \: \: \beta = 4 \\ \alpha + \beta = - 3 + 4 \\ \alpha + \beta = 1 \\ \alpha . \beta = - 3 \times 4 \\ \alpha . \beta = - 12 \\ p(x) = {x}^{2} - ( \alpha + \beta )x + \alpha . \beta \\ p(x) = {x}^{2} - 1x + ( - 12) \\ p(x) = {x}^{2} - x - 12$

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