Chemistry, asked by gayatricaterers, 8 months ago

Which of the following represents the correct set of four quantum numbers of 3d orbital
electron ?
(B) n = 3, 1 = 2. m=2, =0
(A) n=3, 1-3, m2, $= 4
2
1
(C) = 3, 1 = 2, m= l, S=+
2
(D) n = 4, 1= 2. m = 2, S=0​

Answers

Answered by Anonymous
6

Explanation:

The following set of quantum numbers is correct for an electron in 3d orbital.

n=3,l=2,m=−2,s=+

2

1

For s,p,d and f orbitals, l=0,1,2,3 respectively.

When l=2, m can have values −2,−1,0,+1,+2

The spin quantum number s can have value +

2

1

or −

2

1

.

Hence, option C is correct.

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Answered by presentmoment
0

Answer: Option C is the correct answer.

Explanation:

  1. n represents 'principal quantum number'.
  2. Here for 3d orbital , n should be 3.
  3. m stands for magnetic quantum number.
  4. m will be equal to -2 to +2.
  5. s stands for spin angular momentum.
  6. s will be equal to +2.
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