Which of the following represents the correct set of four quantum numbers of 3d orbital
electron ?
(B) n = 3, 1 = 2. m=2, =0
(A) n=3, 1-3, m2, $= 4
2
1
(C) = 3, 1 = 2, m= l, S=+
2
(D) n = 4, 1= 2. m = 2, S=0
Answers
Answered by
6
Explanation:
The following set of quantum numbers is correct for an electron in 3d orbital.
n=3,l=2,m=−2,s=+
2
1
For s,p,d and f orbitals, l=0,1,2,3 respectively.
When l=2, m can have values −2,−1,0,+1,+2
The spin quantum number s can have value +
2
1
or −
2
1
.
Hence, option C is correct.
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Answered by
0
Answer: Option C is the correct answer.
Explanation:
- n represents 'principal quantum number'.
- Here for 3d orbital , n should be 3.
- m stands for magnetic quantum number.
- m will be equal to -2 to +2.
- s stands for spin angular momentum.
- s will be equal to +2.
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