Question

which of the following set of quantum numbers is not possible for an electron in ground state of an atom with atomic number 19
(a) n= 2, l= 0, m= 0
(b)n =2, l= 1, m=0
(c)n= 3, l= 1, m=-1
(d) n=3, l=2, m=2

Answer 1

For atomic number 19, the electronic configuration will be - 1s2 2s2 2p6 3s2 3p6 4s1

So the correct option will be D because -

-In this option m = 2 and the value of m can only be between - m to +m, thus it means that the value of l = 2.

-The value of is 2 only for the d shell and since the electrons do not occupy d shell in the ground state of the atom thus this configuration is not possible.

Answer 2

Answer:6

Explanation:

None of the above option is correct

The correct option should be

n=4 l=0 m=0 s=+½

Atm.no. 19 means the element is potassium(K)

Eelctronic config. is 1s² 2s² 2p6 3s² 3p6 4s¹