Question

which of the following should be added
to make x⁴+64 a perfect samare​

Answer 1

Answer:

Step-by-step explanation:

Most people trying to factor this expression would say that it is irreducible, that is, it cannot factor at all. I will show you a trick that consist of including two terms that not appear in the original expression.

x4 + 64 = x4 + 16x2 - 16x2 + 64

The two terms 16x2 and -16x2 appear by considering the square root of x4 and by dividing the original constant by the leading exponent (64 ÷ 4 = 16). Then, you change the position of the negative term to the last position:

x4 + 16x2 - 16x2 + 64 = x4 + 16x2 + 64 - 16x2

The first three terms form a perfect square trinomial, which can be easily factored. The last term can be rewritten considering the square root concept.

x4 + 16x2 + 64 - 16x2

= (x2 + 8)(x2 + 8) - (4x)2

= (x2 + 8)2 - (4x)2

The preceding expression is a difference of two sqaures. Considering the pattern for this type of factorizaion (a2 - b2), a equals x2 + 8 while b = 4x. So, knowing that a2 - b2 = (a + b)(a - b), we have

(x2 + 8)2 - (4x)2 = (x2 + 8 + 4x)(x2 + 8 - 4x),

which gives the solution to the exercise.

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Answer 2

16x^2 must be added to make it a perfect square.

Reason:
(X^2+8)^2 = x^4 + 16x^2 + 64

The identity used is:
(a+b)^2 = a^2+2ab+b^2