Which of the following statement is correct with
respect to an electron having de-Broglie
wavelength in a Bohr’s orbit of He+ ion, equal to
1.59 πÅ?
(1) The electron is present in 2nd Bohr’s orbit of
He+ ion
(2) On de-excitation to ground state, emitted
photon(s) may lie in infrared or visible region
(3) Total energy of electron in given Bohr’s orbit
is – 3.4 eV
(4) On de-excitation the maximum wavelength of
emitted photon is 1644 Å (approx.)
(only one choice correct)
Answers
Answered by
9
Answer:
(2) On de-excitation to ground state, emitted
photon(s) may lie in infrared or visible region
Explanation:
it is correct
Answered by
0
Answer:
4 th option
Explanation:
solve by using formula 2πr/n
bhonsike
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