Chemistry, asked by panchokakadosumore, 2 months ago

Which of the following statement is correct with

respect to an electron having de-Broglie

wavelength in a Bohr’s orbit of He+ ion, equal to

1.59 πÅ?

(1) The electron is present in 2nd Bohr’s orbit of

He+ ion

(2) On de-excitation to ground state, emitted

photon(s) may lie in infrared or visible region

(3) Total energy of electron in given Bohr’s orbit

is – 3.4 eV

(4) On de-excitation the maximum wavelength of

emitted photon is 1644 Å (approx.)
(only one choice correct)​

Answers

Answered by itzpriyanshi437
9

Answer:

(2) On de-excitation to ground state, emitted

photon(s) may lie in infrared or visible region

Explanation:

it is correct

Answered by dawarpriyanshu28
0

Answer:

4 th option

Explanation:

solve by using formula 2πr/n

bhonsike

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