Question

which of the following values satisfied 2x+1/3x-1= 3/2 ? (a)x=1 (b)x=-1 (c)x=2 (d)x=-3
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Option (a) x = 1 is the correct answer.

Explanation:

Given that, $\frac{2x+ 1}{3x -1} = \frac{3}{2}$

• For x = 1

⇒On putting x = 1 in the given equation.

⇒ $\frac{2x+ 1}{3x -1} = \frac{3}{2}$

⇒ $\frac{2(1)+ 1}{3(1) -1} = \frac{3}{2}$

⇒$\frac{2 + 1}{3 -1}$ =  $\frac{3}{2}$ = $\frac{3}{2}$

So, x = 1 satisfied the given equation.

• For x = -1

On putting x = -1 in the given equation we get,

⇒$\frac{2x+ 1}{3x -1} = \frac{3}{2}$

⇒$\frac{2(-1)+ 1}{3(-1) -1} = \frac{3}{2}$ ⇒ $\frac{-2 +1}{-3 -1}$ = $\frac{-1}{-4}$ ≠ $\frac{3}{2}$

So, here we can see that x = -1 not satisfied the equation.

• For x = 2

On putting x = 2 in the given equation

⇒$\frac{2x+ 1}{3x -1} = \frac{3}{2}$

⇒$\frac{2(2)+ 1}{3(2)-1} = \frac{3}{2}$ ⇒ $\frac{5}{5}$ = 1 ≠ $\frac{3}{2}$

• For x = -3

On putting x = -3 in the given equation

⇒ $\frac{2(-3)+ 1}{3(-3) - 1} = \frac{3}{2}$

⇒ $\frac{-6+ 1}{-9 - 1} = \frac{3}{2}$

⇒ $\frac{-5}{-10}$ = $\frac{1}{2}$ ≠ $\frac{3}{2}$

Final answer:

Hence, (a) x = 1 which satisfied the given equation.

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