Question

Which of the following will contain maximum
number of molecules?
(1) 100L CO(g) at NTP
2) 10g of H2(g) at NTP
(3) 1L of H2O(l)
(4) 1000 g of C12H22O11(s) at NTP​

Answer 1

Answer:

100 L at NTP = 100/22.4 moles = 4.464 moles 10 g H2 at NTP =10/2= 5 moles 1 L liqiud water has 1000g mass(density=1gcm-3). So no of moles =1000/18=55.55moles 1000g C12H22O11= 1000/342 =2.92 moles So maximum number of moles is present in 1L water.