Chemistry, asked by sasibro8780, 8 months ago

Which of the following will contain maximum number of molecules
1)100L CO2 at NTP
2)10g H2 at NTP
3)1L of H20(l)
4)1000g of C12H22011(S) at NTP

Answers

Answered by tsradhanjali3
1

Answer:

2)10g of H2

Explanation:

100L of CO2=100/22.4*6*10^23

10g of H2=5*6*10^23

1L of H2O=1/22.4*6*10^23

1000g of C12H22O11=1000/342*6*10^23

Max no of molecules are present in

10g H2 at NTP

Answered by ashirrehaan03
5

Answer: (3) option..

Explanation:

(1) n = 100/22.4=4.46

so no of molecules = 4.46*Na

(2) n =10/2=5

so no of molecules = 5*na

(3)

1L of h20..but h20 isn't at NTP.

D=M/V

M=1000g

n=1000/18=55.5

no of molecules = 55.5*Na

(4)

n=1000/342=2.92

no of molecules = 2.92*na

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