Which of the following will give yellow precipitate with I2/NaOH
(1)CH3CH2COCH2CH3(2)CH3COOCOCH3(3)CH3CONH2(4)CH3CH(OH) CH2CH3
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The Acetyl group that is ( CH₃ - C=0) containing compounds and also CH₃CH - OH (meaning it can be oxidized) will give a yellow precipitate when reacted with
12 / OH⁻ and in this case 12/NAOH which give OH⁻ for reaction.
From the explanation above we can identify an Acetyl group.
The Acetyl compound in the answers above is :
Option 4 which is :
CH₃CH(OH) CH₂CH₃.
12 / OH⁻ and in this case 12/NAOH which give OH⁻ for reaction.
From the explanation above we can identify an Acetyl group.
The Acetyl compound in the answers above is :
Option 4 which is :
CH₃CH(OH) CH₂CH₃.
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