Which of the given orbitals are possible? 1p, 2s, 2p and 3f
Answers
In the given example, only the 2s and 2p are possible. In the first shell, there is only the 1s orbital, as this shell can have a maximum of only 2 electrons. Therefore, the 1p orbital doesn't exist. In the second shell, both 2s and 2p orbitals exist, as it can have a maximum of 8 electrons.
2s and 2p orbitals are possible
Explanation:
Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....
Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
1. For 1 p:
n=1 and l can have value 0 to (n-1) i.e. 0 only. For p, l=1 which is not possible.
2. For 2s :
n=2 and l can have value 0 to (n-1) i.e. 0 and 1 only. For s, l=0 which is possible.
3. For 2p :
n=2 and l can have value 0 to (n-1) i.e. 0 and 1 only. For p, l=1 which is possible.
4. For 3f:
n=3 and l can have value 0 to (n-1) i.e. 0, 1 and 2 only. For f, l=3 which is not possible.
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