Which of the smallest five digit number is divisible by 41?
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41×1000=41000(5-digit number)
41000/4 = 20500/2
=10250
10250 = 41×250
Within 250,there are 6 multiples of 41 (i.e,246)
=>10250-246=10004.
10004÷41 = 244
Hence,
10004 is the smallest five digit number which is divisible by 41.
41000/4 = 20500/2
=10250
10250 = 41×250
Within 250,there are 6 multiples of 41 (i.e,246)
=>10250-246=10004.
10004÷41 = 244
Hence,
10004 is the smallest five digit number which is divisible by 41.
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