Question

which of these in a way to convert 15/√63+√20 to an equivalent number whose denominator is a rational number?​

Answer 1

$\underline{\textsf{Given:}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}}$

$\underline{\textsf{To find:}}$

$\textsf{A number equivalent to the given number}$

$\textsf{whose denominator is a rational number}$

$\underline{\textsf{Solution:}}$

$\textsf{Here,we have to rationalize the denominator of the given number}$

$\mathsf{Consider,}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}}$

$\textsf{To rationalize the denominator multiply both numerator and}$

$\mathsf{denominator\;by\,\sqrt{63}-\sqrt{20}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}=\dfrac{15}{\sqrt{63}+\sqrt{20}}{\times}\dfrac{\sqrt{63}-\sqrt{20}}{\sqrt{63}-\sqrt{20}}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}=\dfrac{15(\sqrt{63}-\sqrt{20})}{(\sqrt{63}+\sqrt{20})(\sqrt{63}-\sqrt{20})}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}=\dfrac{15(\sqrt{63}-\sqrt{20})}{\sqrt{63}^2-\sqrt{20}^2}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}=\dfrac{15(\sqrt{63}-\sqrt{20})}{63-20}}$

$\mathsf{\dfrac{15}{\sqrt{63}+\sqrt{20}}=\dfrac{15(\sqrt{63}-\sqrt{20})}{43}}$

$\therefore\mathsf{The\;required\;equivalent\;number\;is\;\dfrac{15(\sqrt{63}-\sqrt{20})}{43}}$

$\underline{\textsf{Find more:}}$

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If x = √7+ √3 and xy = 4, then x4 + y4 =​

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17/3√2+1 rationalise the denominator

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Answer 2

Answer:

15uponroot63 gosbzgJbaoaoknm

vaonag16628

288