Question

which one of the following is the weakest base? 1) methylamine. (2) aniline. (3) piperdine. (4) anline​

Answer 1

Answer:

aniline

Explanation:

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Answer 2

Answer:

Weak bases are basic compounds that, when dissolved in solutions, do not entirely separate into their constituent ions. As a result, when a weak base is dissolved in a solution, some of it dissociates into hydroxide anions and the appropriate conjugate acid while the rest remains undissociated.

Explanation:

Methyl amine is a primary aliphatic amine.

Aniline is a primary amine as well as aromatic in nature.

Piperidine is a secondary amine as well as an aliphatic amine.

Because the lone pair of nitrogen atoms in aliphatic amines are not delocalized like they are in aromatic amines, piperidine and methyl amine are more basic than piperidine. So, aniline is a weak base.

Compared to primary and tertiary amines, secondary amines are more basic. The stability of the chemical generated after receiving a proton is used to explain the basicity of amines (donating the lone pair of nitrogen atoms to a proton). Alkyl groups are groups that donate electrons.

Thus, piperidine is more basic than methylamine.

Hence, the correct option is (2) aniline or (4) aniline.

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