Question

Which one of the following will have largest number of atoms? (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2(g)

Answer 1

i) 1gAu =1/197mol =1/197×1023 atoms

ii) 1gNa =1/23 mol=1/23×6.022×1023 atoms

iii) 1gLi =1/7 mol=1/7×6.022×1023 atoms

iv)1g of CI2 (g)=1/71 mol=1/71×6.022×1023 atoms ⚫⚪️️️️️⭐☀️⛱♥️♦️❣❤❤❤❤⭐⛱♥️️️⚪☀️♦️️⚪️♥️♦️❣❣⚘⚘⚘⚘⛱♦️♦️⛱♦️♦️

Thus, 1g Li is the right answer

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Answer 2

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