Question

Which one rational number is in standard form:-

-5/8
9/12
4/-10
none of these

Answer 1

$\large{\underbrace{\sf{\purple{required \: solution:}}}}$

Fractions given,

• $\sf \dfrac{ - 5}{8}$

• $\sf \dfrac{9}{12}$

• $\sf \dfrac{ - 4}{10}$

We need to find which rational numbers are in standard form.

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According to the question,

As we know ,

• A rational number is said to be standard form only if the denominator is a positive integer.
• Numerator and denominator should not have any common factors other than 1.

Now , let's do:

$\blue{ 1)\sf \dfrac{ - 5}{8} }$

• In this rational number denominator is a positive integer.
• Numerator and denominator have no common factors other than 1.
• Thus, It is not in standard form.

$\rightarrow\boxed{ \purple{ \sf It \: is \:not \: in \: standard \: form }}$

$\blue{ \sf2)\dfrac{9}{12} }$

• In this rational number denominator is a positive integer.
• Numerator and denominator have a common factor ( 3 ).
• Thus , it is in standard form.

$\rightarrow\boxed{ \purple{ \sf It \: is \: in \: standard \: form }}$

$\blue{ \sf3)\dfrac{ - 4}{10} }$

• In this rational number denominator is a positive integer.
• Numerator and denominator have a common factor ( 2 ).
• Thus , It is not in standard form.

$\rightarrow\boxed{ \purple{ \sf It \: is \: not\: in \: standard \: form }}$

Hence , First option is in standard form ( -5 / 8 ) ✓

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