Which option is it...
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metre per second inveres
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Since the output of the sine function is dimensionless, its input must be dimensionless too.
Hence, 4πßγ/α should be dimensionless.
4π is itself a dimensionless value.
Hence, βγ/α should be dimensionless.
So, according to the given data, β/α has the unit ms-¹/s-¹ = m.
Let γ's unit be 'u'.
Therefore, for the input of sine to be dimensionless,
mu = 1
⇒ u = /m = m-¹.
Hence, the correct answer is /m (per metre, or metre inversed (m-¹)).
Hence, 4πßγ/α should be dimensionless.
4π is itself a dimensionless value.
Hence, βγ/α should be dimensionless.
So, according to the given data, β/α has the unit ms-¹/s-¹ = m.
Let γ's unit be 'u'.
Therefore, for the input of sine to be dimensionless,
mu = 1
⇒ u = /m = m-¹.
Hence, the correct answer is /m (per metre, or metre inversed (m-¹)).
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