Science, asked by nick469, 11 months ago

Which product is obtained when methyl
cyanide is reduced by sodium and ethyl
alcohol ?​

Answers

Answered by sangeetakk199
5

The product will be primary amine methylamine (NH2).

Answered by mindfulmaisel
3

Ethylamine is obtained when methyl cyanide is reduced by ‘sodium and ethyl alcohol’.

Explanation:  

  • Sodium and ethyl alcohol will give free hydrogen ion to the methyl cyanide. Hence the cyanide Bond present in methyl cyanide will get reduced.  
  • On reduction of the cyanide a primary amine is formed. In this case the compound that will be formed after complete reduction of methyl cyanide is ethyl amine.  
  • This is the main product that will be formed after the reaction of methyl cyanide with Sodium and ethyl alcohol. This is a reduction type of reaction.

Learn more about Ethylamine

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