Question

Which reaction is not feasible?
(a) 2KI + Br₂ → 2KBr + I₂
(b) 2KBr + I₂ → 2KI + Br₂
(c) 2KBr +Cl₂ → 2KCl + Br₂
(d) 2H₂O+ 2F₂ → 4HF +O₂

Answer 1

Answer:

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Answer 2

The required option (c) $2KBr +Cl_2$ → 2KCl + $Br_2$ is correct.

Explanation:

The reactions are based on the reactivity order of Halogens are:

F > O > Cl > Br  > I  , is the single displacement reaction.

Check options:

 (a) $2KI + Br_2$  → $2KBr + I_2$, is feasible.

(b) $2KBr + I_2$ → $2KI + Br_2$, is feasible.

(c) $2KBr +Cl_2$ → 2KCl + $Br_2$, is not feasible.

since, Iodinde cannot displace Br due to its less reactivity.

(d) $2H_2O+ 2F_2$ → 4HF + $O_2$

Thus, the required option (c) $2KBr +Cl_2$ → 2KCl + $Br_2$ is correct.