Which shows two expressions that are equivalent to (Negative 7) (Negative 15) (Negative 5)? (Negative 7) (Negative 75) and (Negative 1) (525) (Negative 1) (525) and (35) (Negative 15) (35) (Negative 15) and (115) (negative 5) (Negative 1) (525) and (115) (negative 5)
Answers
Answer:
-525 and (35)(-15)
Step-by-step explanation:
You can calculate the result of this expression as follows:
(-7)(-15)(-5) = (-1)³(7×15×5)
= -(7×15×5)
= -525
as, (-1)ⁿ = 1 if n is even and (-1)ⁿ = -1 if n is odd.
We already saw that -525 is equivalent to the expression.
Furthermore:
(-7)(-15)(-5) = (-15)(-7)(-5)
= (-15)(-1)²(7×5)
= (-15)(7×5)
= (-15)(35).
so the second expression is also equivalent.
You can discard the third and fourth answers because 115×5=575≠525. The first one is also discarded, because (-7)(75)=525≠-525.
Given (- 7) (-15) (- 5)
To Find : Which two expressions that are equivalent (- 7) (-15) (- 5)
(–7)(–75) and (–1)(525)
(–1)(525) and (35)(–15)
(35)(–15) and (115)(–5)
(–1)(525) and (115)(–5)
Solution:
(- 7) (-15) (- 5)
= (105)(-5)
= - 525
(–7)(–75) and (–1)(525)
= 525 & - 525
not Equal
(–1)(525) and (35)(–15)
= -525 and - 525
Both Equal to (- 7) (-15) (- 5)
(35)(–15) and (115)(–5)
= -525 and - 575
not Equal
(–1)(525) and (115)(–5)
= -525 and - 575
not Equal
(–1)(525) and (35)(–15) are equivalent to (- 7) (-15) (- 5)
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