Which substance serves as reducing agent in
the following reaction ?
14H⁺+ Cr₂O²₇ + 3Ni ⟶
2Cr³⁺+ 7H₂O + 3Ni²⁺
(a) H₂O (b) Ni
(c) H+ (d) Cr₂O²₇
Answers
Answered by
2
Explanation:
The Redbox reaction is given below:
14H+Cr2O72+3Ni→2Cr 3+ +7H 2 O+3Ni 2+60+3+2
As Ni is oxidised, it will act as reducing agent
Answered by
1
Answer:
Heyaa✌️✌️
Your right answer is:- b) Ni
As Ni is oxidised from 0 to +2, it will acts as reducing agent.
Hope it helped you.
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