Question

which term of A.P.:-134,129,124...... is its first negative term.(hint:- an˂0)

Answer 1

in A.p.

Tn = a+ (n–1)d

for

Tn < 0

a+(n–1)d < 0

134 + (n–1)(-5 ) < 0

n –1 < 134/5

n – 1 < 26.8

n < 27.8

here n is a neutral number

so its maximum possible value which is integer n = 27

so in A.p. 27 th term is first negetive term .

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