which term of a.p. 163,160,157....... is the first negative term?
Answers
Answered by
11
a=163, d=-3
so for first negative term
a+(n-1)d<0
163+(n-1)-3<0
-3n<-166
3n>166
n>166/3
n>55•333
so for first negative term the n must be greater then 55•333
so the first negative term is 56
so for first negative term
a+(n-1)d<0
163+(n-1)-3<0
-3n<-166
3n>166
n>166/3
n>55•333
so for first negative term the n must be greater then 55•333
so the first negative term is 56
adirustom:
I DONT KNOW HOW TO DO IT
thanks
CAN U PLEASE TELL ME HOW THIS SIGN > < CHANGE
tm kis class main ho bhai
10
????,
you have to know inequality
in equality how does the sign flips please tell
when you change the sign then inequality changes okm
Oh Thnks Agian
Answered by
5
a = 163, d= - 3
The nth term = a +(n-1)d
Using this formula solve it.
163+(n-1)(-3)
0>163+(n-1)(-3)
n>(166/3)
n=56th term
so 56th term is the first negative term in this AP
The nth term = a +(n-1)d
Using this formula solve it.
163+(n-1)(-3)
0>163+(n-1)(-3)
n>(166/3)
n=56th term
so 56th term is the first negative term in this AP
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