Question

which term of A.P 3,15,27,39... will be 132 more than its 54th term?

Answer 1

Given a = 3, d = 12, n = 54.

We know that an=a+(n-1) * d   ---------- (1)

                            = 3 + (54-1) * 12

                            = 3 + 53 * 12

                            = 639.

  a54 = 639.


Given that the term is 132 more than its 54th term = 639 + 132 = 771.

on substituting in (1), we get

771 = 3 + (n-1) * 12

768 = (n-1) * 12

768/12 = n-1

n-1 = 64

n = 65.

Therefore the 65th term is 132 more than its 54th term.


Hope this helps!

Answer 2

Answer:

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