Math, asked by pushkaru, 6 months ago

Which term of A.P. 72, 70, 68, 66, ... is 40?
(A) 16
(B) 17
(C) 18
(D) 20

Answers

Answered by psamayamantri
1

Answer:

17th

Step-by-step explanation:

a=72,d=70−72=68−70=66−68=−2

a

n

=40

General term : a

n

=a+(n−1)d

a+(n−1)d=40

72+(n−1)(−2)=40

72−2n+2=40

2n=34

n=17

Answered by Snapskg730
1

Answer:

d = 70-72 = -2

an = a + (n-1)d

40 = 72 + (n-1) -2

40-72 = (n-1)-2

-32 = (n-1)-2

-32/-2 = n-1

16 = n-1

n = 16+1 = 17

(b) 17

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