Which term of A.P of 5,13,22.....is 181
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Answered by
0
Heya!
We know that
an = a + (n-1)d
an = 181 (last term of AP)
a= 5 (first term of AP)
d= 13-5 = 8 (common difference)
so calculate 'n'
181 = 5+ (n-1) 8
181 -5 = (n-1)8
176/ 8 = n-1
n-1= 22
n= 23
so,
23 Term of this AP will be 181!
:)
We know that
an = a + (n-1)d
an = 181 (last term of AP)
a= 5 (first term of AP)
d= 13-5 = 8 (common difference)
so calculate 'n'
181 = 5+ (n-1) 8
181 -5 = (n-1)8
176/ 8 = n-1
n-1= 22
n= 23
so,
23 Term of this AP will be 181!
:)
Answered by
0
HEY HERE IS YOUR ANSWER...
it is given that,
a = 5
d = 8
a n = 181
n = ?
solution:
a n = a + (n-1)d
181 = 5 + (n-1)8
176 = 8n - 8
184 = 8n
n = 23.
HOPE THIS QOULD HELP YOU...
it is given that,
a = 5
d = 8
a n = 181
n = ?
solution:
a n = a + (n-1)d
181 = 5 + (n-1)8
176 = 8n - 8
184 = 8n
n = 23.
HOPE THIS QOULD HELP YOU...
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