Math, asked by ashishmoundekar, 1 year ago

which term of an A.P 3,8,13,18......is 78?

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Answers

Answered by gaurav2013c
29
a = 3
d = 5

Tn = 78

=> a +(n-1)d = 78

=> 3+ (n-1)5 = 78

=> (n-1)5 = 75

=> n-1 = 15

=> n = 16


16th term of this AP is 78
Answered by Anonymous
9

For the following A.P : 3,8,13,18,------, 78 


First term (t1) = a = 3,common difference (d) = 8 - 3 = 5 and last term (tn) = 78 



The general term of A.P is 


tn = a + (n - 1) d 


78 = 3 + (n - 1)5 


78 = 3 + 5n - 5 


78 = - 2 + 5n 


78 + 2 = 5n 


80 = 5n 


80/5 = n 


16 = n 


n= 16 



16th term of A.P : 3,8,13,18,is 78.



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