Question

Which term of an AP 13, 19, 25, 31...... 103​

Answer 1

Step-by-step explanation:

common difference d=t2-t1

d=6

tn=a+(n-1)d

we have to find which term (n) is 103

therefore

103=13+(n-1)6

103=13+6n-6

103=7+6n

6n=96

n=16

hence solved:)

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