Question

which term of an AP 13 21 29 .........
will be 48 less than 10th term ???

Answer 1

We have,

AP : 13, 21, 29, .....

Here, common difference (d) = 8

Let the desired term be x

ATQ ;

$= > x = (10th \: \: term) - 48 \\ = > x = a + (n - 1)d - 48 \\ = > x = 13+9(8) - 48 \\ = > x = 85 - 48 = 37$

So, nth term = x = 37

=> a + (n - 1)d = 37

=> 13 + (n - 1)8 = 37

=> n - 1 = 3

=> n = 4

Hope it'll help you.....