Question

which term of an AP 5,12,19,26,33,... will be 35 more than its 12th term​

Answer 1

Answer:

17 is the answer

Step-by-step explanation:

a=5

d=12-5=7

now, a12=a+11d

=5+11(7)

=77+5=82

now,let an =35+82=117

use, an=a+(n-1)d

117=5+(n-1)7

117=5+7n-7

117=7n-2

119=7n

or n = 119/7=17

hope this helps

Answer 2

The answer is 15th term

Given: 5, 12, 19, 26, 33

To find: The term which is 35 more than 12th term

Solutions: 5, 12, 19, 26, 33.. is a AP series

from the series first time a = 5 and common difference d = 12 - 5 = 7  

Here, to find the term which is 35 more than 12th term,

we need to know 12th term

As we know nth term of AP, $T_{n}$ = a+(n-1)d  

⇒  $T_{12}$  = a + (n-1)d = 5 + ( 12 - 1) 7 = 5 + (11)7 = 5 + 77 = 82

⇒ the value of the term which is 35 more than 82 = 82 + 35 = 117  

⇒ Let us assume that $n^{th}$ term in AP = 117

⇒ T$_{n}$ = a +(n-1)d = 5 +(n-1)7 = 117

⇒  (n-1)7 = 117 - 5

⇒  (n-1) 7 = 112

⇒  n - 1 = 16      ⇒ n = 15  

Therefore, 15th term in given AP is 35 more than 12th term

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